 | | | ip command line question | ip command line question 2003-07-08 - By Stephen Liu
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Hi Ryan,
Thanks for your advice.
On Wed, 2003-07-09 at 01:18, Ryan McDougall wrote:
>
> - snip -
> >
> > # ip addr
> > 1: lo: <LOOPBACK,UP> mtu 16436 qdisc noqueue
> > link/loopback 00:00:00:00:00:00 brd 00:00:00:00:00:00
> > inet 127.0.0.1/8 brd 127.255.255.255 scope host lo
> > 2: eth0: <BROADCAST,MULTICAST,UP> mtu 1500 qdisc pfifo_fast qlen 100
> > link/ether 00:50:fc:39:3b:59 brd ff:ff:ff:ff:ff:ff
> > 3: ppp0: <POINTOPOINT,MULTICAST,NOARP,UP> mtu 1492 qdisc pfifo_fast qlen
> > 3
> > link/ppp
> > inet 202.123.68.48 peer 202.123.71.254/32 scope global ppp0
> >
> > What does point 3. above indicate?
>
> It indicates that you are connecting to the net via the Point to Point
> Protocol. And this is usually used with some sort of DSL.
Noted
What does "POINTOPOINT,MULTICAST,NOARP,UP> mtu 1492 qdisc pfifo_fast
qlen 3" indicate?
> > What command line to be issued to find the current ip address assigned
> > by ISP (broadband)?
>
> Actually the ip address is in point 3:
> "inet 202.123.68.48 peer 202.123.71.254/32 scope global ppp0"
> This inet line tells you your ip address, 202.123.68.48t
Noted with thanks
What does "peer 202.123.71.254/32 scope global ppp0" indicate?
and
B.Regards
Stephen
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